Equation of a Circle
Equation of a circle with centre (a,b) and radius r.
PR = x - a, PQ = r
QR = y - b
Since ΔPQR is the right angle triangle, we have: PQ2 = PR2 + QR2
r2 = (x - a)2 + (y - b)2
if the center of the circle is the origin (0, 0), the equation becomes x2 + y2 = r2
General Equation of a Circle
From (x - a)2 + (y - b)2 = r2
r2 - 2ax + a2 + y2 - 2by + b2 - r2 = 0
x2 + y2 - 2ax - 2by + a2 + b2 - r2 = 0
The above equation can be written as x2 + y2 + 2gx + 2fy + c = 0
Where a = -g, b = -f, c = -a2 + b2 - r2
Hence: x2 + y2 + 2gx + 2fy + c = 0 is called the general equation of a circle.
Equation of a circle with centre (a,b) and radius r.
PR = x - a, PQ = r
QR = y - b
Since ΔPQR is the right angle triangle, we have: PQ2 = PR2 + QR2
r2 = (x - a)2 + (y - b)2
if the center of the circle is the origin (0, 0), the equation becomes x2 + y2 = r2
General Equation of a Circle
From (x - a)2 + (y - b)2 = r2
r2 - 2ax + a2 + y2 - 2by + b2 - r2 = 0
x2 + y2 - 2ax - 2by + a2 + b2 - r2 = 0
The above equation can be written as x2 + y2 + 2gx + 2fy + c = 0
Where a = -g, b = -f, c = -a2 + b2 - r2
Hence: x2 + y2 + 2gx + 2fy + c = 0 is called the general equation of a circle.
Equation of a Circle
Equation of a circle with centre (a,b) and radius r.
PR = x - a, PQ = r
QR = y - b
Since ΔPQR is the right angle triangle, we have: PQ2 = PR2 + QR2
r2 = (x - a)2 + (y - b)2
if the center of the circle is the origin (0, 0), the equation becomes x2 + y2 = r2
General Equation of a Circle
From (x - a)2 + (y - b)2 = r2
r2 - 2ax + a2 + y2 - 2by + b2 - r2 = 0
x2 + y2 - 2ax - 2by + a2 + b2 - r2 = 0
The above equation can be written as x2 + y2 + 2gx + 2fy + c = 0
Where a = -g, b = -f, c = -a2 + b2 - r2
Hence: x2 + y2 + 2gx + 2fy + c = 0 is called the general equation of a circle.
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